solve the pair of linear equations graphically and find the vertices of a triangle formed by these lines and y-axis. x-y=-1, 3x +2y-12=0.
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In equation first x - y = -1
x = y - 1
put this value in equation 2
3x+2y-12=0
3(y-1)+2y-12=0
3y-3+2y-12=0
5y-15=0
5y=15
y=15/5
y=3
y=3
x-y=-1
x-3=-1
x=3-1
x=2
y=3
x=2
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