Question

solve the pair of linear equations
x+18y=19 and 3x+4y=1
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Answer 1

Answer:-

$x + 18y = 19 - - - - - 1 \times 3\\ \\ 3x + 4y = 1 - - - - - 2 \\ \\ solve \: both \: equations \\ \\ 3x + 54y = 57 \\ 3x + 4y = 1 \\ - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: 50y = 56 \\ \\ y = \frac{56}{50} = \frac{28}{25}$