Solve the pair of linear equations x + 2 y + 2 0and
3 x + 2 y =0 graphically. Shade the
triangular region represented by the given equations and the y-axis. Also find the area
of this region.
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Answer:
x−y+1=0
x−y=−1 ...(i)
3x+2y−12=0
3x+2y=12 ...(ii)
x−y=−1
y=1+x
x 0 −1
y 1 0
Plot (0,1) and (1,2) on graph and join them to get eqn (i)
For 3x+2y=12
⇒2y=12−3x
⇒r=
2
12−3x
x 0 4
y 6 0
Plot point (0,6) and (4,0) on graph and join them to get eqn (ii)
△ABC is the required triangle with coordinates of A as (2,3),B(−1,0) and C(4,0).
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