Question

. Solve the pair of linear equations: x-4y=13 and 3x+2y+3=0 , by Substitution method OR Elimination method

Answer 1

Answer:

Step-by-step explanation: First by substitution method

x - 4 y = 13,

x = 13 +4 y,.............................1

3 x + 2 y + 3 = 0, now substitute value of x from ..1

3(13 + 4 y) + 2 y + 3 = 0

39 + 12 y +2 y + 3 = 0

14 y + 42 = 0

14 y = -42

y = -3

put value of y in equation 1

x = 13 + 4(-3)

x = 13 - 12 = 1

BY ELIMINATION METHOD,

x - 4 y = 13

multiply by three on both sides,

3 x - 12 y = 39,

3 x + 2 y = -3,

subtract both equations,

we get,

3 x - 12 y - 3 x  - 2 y = 39 + 3

-14 y = 42,

y = -3

substitute value of y in 1 and we get x = 1.

Answer 2

Answer:

wrong answer right answer is y=-3 and x=1