Question

solve the pair of liner equation
x+3y=6 ,2x-3y= 12​

Answer 1

Answer:

correct answer is X= 6 and Y= 0.

Mark as brilliant.and follow me

Answer 2

Answer:

$x + 3y = 6 \: and \: 2x - 3y = 12$

$\frac{a1}{a2} = \frac{1}{2} \frac{b1}{b2} = \frac{3}{ - 3} \frac{c1}{c2} = \frac{6}{12}$

Thus,

$\frac{a1}{a2} = \frac{1}{2} \frac{b1}{b2} = \frac{1}{ - 1} \frac{c1}{c2} = \frac{1}{2}$

$\frac{a1}{a2} \: is \: not \: equal \: to \: \frac{b1}{b2}$

Therefore the equation has

The equation has a unique(one) solution and has intersecting lines.

Hope You Like The Answer!!!!