Question

Solve the pair of liner equations by elimination method
3x + 2y = 12
5x - 2y = 4

Answer 1

Hey...!! HERE IS YOUR ANSWER...!!

3x + 2y = 12
x = 12 - 2y / 3.........(1)......

5x - 2y = 4
x = 4 + 2y / 5..........(2).....

FROM EQN... 1 AND 2 ,

12 - 2y / 3 = 4 + 2y / 5
60 - 10y = 12 + 6y
60 - 12 = 6y + 10y
16y = 48
y = 3....

SUBSTITUTE THE VALUE OF Y IN EQN. 1

x = 12 - 2y / 3
x = 12 - 2×3 / 3
x = 12 - 6 / 3
x = 6 / 3
x = 2.....

$\textbf{x = 2 ; y = 3}$

HOPE IT'S WILL HELP YOU A LOT...!!
@ujjwalusri

Answer 2

The solution of a pair of linear equations is (2,3); i.e. $\bf \: x = 2 \: and \: y = 3$.

Given:

• A pair of linear equations.
• $3x + 2y = 12$ and
• $5x - 2y = 4$

To find:

• Solve the pair of linear equations by elimination method.

Solution:

Step 1:

Add both equations.

Let

$3x + 2y = 12 \: ...eq1$

and

$5x - 2y = 4 \: \: ...eq2$

Add both eqs 1 and 2.

$3x + 2y = 12 \\ 5x - 2y = 4 \\ - - - - - - \\ 8x = 16 \\ - - - - - -$

$\implies x = \frac{16}{8}$

$\implies \: \bf x = 2$

Step 2:

Find the value of y.

Put value of x in eq2.

$5(2) - 2y = 4$

$10 - 2y = 4$

$\implies - 2y = 4 - 10$

$\implies 2y = 6$

$\implies y = \frac{6}{2}$

$\implies \bf y = 3$

Thus,

The solution of a pair of linear equations is (2,3); i.e. $\bf \: x = 2 \: and \: y = 3$.

Learn more:

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2) 3x+2y=8 and 2x-y=3 solve pair of linear equation by elimination method

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