Solve the pair of simultaneous equation by cross multiplication method: 3x+2y-4=0 8x+5y=9
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8x+5y=9_____1st equation
3x+2y=4_____2nd eqtn
From 1st eqn,
8x+5y=9
8x=9-5y
x=9-5y/8
Putting value of x in 2nd eqn
3x+2y=4
3(9-5y)/8+2y=4
3(9-5y)/8+2y=4
3(9-5y)+8(2y)/8=4
3(9-5y)+8(2y)=4×8
27-15y+16y=32
27+y=32
y=32-27
y=5
Putting y=5 in 2nd eqtn
3x+2y=4
3x+2(5)=4
3x+10=4
3x=4-10
3x=-6
x=-6/3
x=-2
Therefore,x=-2 and y=5 is the solution of the given pair of linear equations
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