Math, asked by mathsishard92, 3 months ago

Solve the pair of simultaneous equations:
y²+2y+11=x
x=5-3y

Answers

Answered by ALITEACHEE
3

Answer:

y^2+2y+11 = 5-3y

y^2+2y+11-5+3y =0

y^2+5y+6=0

y^2+3y+2y+6=0

y(y+3)+2(y+3)=0

(y+3)(y+2)=0

y= -3, -2

Answered by onlyone68
3

Step-by-step explanation:

This answer is right

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