Solve the pair of simultaneous equations:
y²+2y+11=x
x=5-3y
Answers
Answered by
3
Answer:
y^2+2y+11 = 5-3y
y^2+2y+11-5+3y =0
y^2+5y+6=0
y^2+3y+2y+6=0
y(y+3)+2(y+3)=0
(y+3)(y+2)=0
y= -3, -2
Answered by
3
Step-by-step explanation:
This answer is right
Attachments:
Similar questions
Biology,
1 month ago
Social Sciences,
1 month ago
World Languages,
1 month ago
English,
3 months ago
History,
3 months ago
India Languages,
9 months ago
World Languages,
9 months ago