Question

solve the pairs of equation x/a–y/b=0 and ax + by = a square + b square​

Answer 1

Step-by-step explanation:

x/a - y/ b = 0 ..........(eqn 1)

ax + by = a2 + b2.......... ( eqn 2)

let us take (1)

x/a = 0 + y/b

x/a = y/b

x = y/b*a

x= ay / b....... ( 3)

now substituting the valve of x in eqn 2

we get,

ax + by = a2 + b2

a ( ay/b) + by = a2 + b2

a2y/b + b/y = a2 + b2

y [ a2/b + b ] = a2 + b2

y [ (a2+b2)/ b ] = a2 + b2

y = (a2 + b2) × b ÷ a2 + b2

y = b ...... (4)

now again substituting the value of y in eqn 1

x/a - y/b = 0

x/ a - b/b = 0

x/a - 1 = 0

x/a = 1

x = a.....(5)

therefore x=a & y= b

you can verify the equation by substituting the final value of x and y and it satisfies the equation