Solve the PDE: + 2 + = 2( − ) + sin( − )
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Step-by-step explanation:
sin(A−B)=
2
1
⇒sin(A−B)=30
o
[∵sin30
o
=
2
1
]
On equating both sides
A−B=30
o
...(1)
cos(A+B)=
2
1
⇒cos(A−B)=cos(60
o
)[∵cos(60
o
)=
2
1
]
On equating both sides
A+B=60
o
..(2)
Adding (1) and (2)
2A=90
o
⇒A=45
o
Putting value of A in (i)
45
o
+B=60
o
⇒B=15
o
Hence A=45
o
; B=15
o
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