Math, asked by shashankhimanshu, 2 months ago

Solve the PDE z^2(p^2+q^2+1)=1

Answers

Answered by itsnasreensahaikh

0

Step-by-step explanation:

z^2(p^2+q^2+1)=1z^2(p^2+q^2+1)=1z^2(p^2+q^2+1)=1

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