Question

solve the polynomial root of 5x^2 -6x+8- root of 5x^2-6x-7=1... its the question of cengage jee.. theory of equation lesson 2 page no.2.2.... proper explanation is not given in the guide.... can you help me in finding solution....it's urgent

Answer 1

Answer:

Let's solve for o.

5x2−6x+8−root(5)x2−6x−7=1

Step 1: Add -5x^2 to both sides.

−5o2rtx2+5x2−12x+1+−5x2=1+−5x2

−5o2rtx2−12x+1=−5x2+1

Step 2: Add 12x to both sides.

−5o2rtx2−12x+1+12x=−5x2+1+12x

−5o2rtx2+1=−5x2+12x+1

Step 3: Add -1 to both sides.

−5o2rtx2+1+−1=−5x2+12x+1+−1

−5o2rtx2=−5x2+12x

Step 4: Divide both sides by -5rtx^2.

−5o2rtx2−5rtx2=−5x2+12x−5rtx2

o2=5x−125rtx

Step 5: Take square root.

o=√5x−125rtx or o=−√5x−125rtx

Answer:

o=√5x−125rtx or o=−√5x−125rtx

Answer 2

Answer:

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