Solve the probability In a family of 3 children , the probability of having at least one boy
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1
p(,alesast 1 boy)=1/3
=1:3
=1:3
seemavishwakarma753:
Your answer is wrong
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The probability that each child will be a boy is 1/2.
The probability that each child will be a girl is 1/2.
The probability of no. boys = 1/2 × 1/2 × 1/2 = 1/8
The probability of at least 1 boy = 1 - the probability of no boys.
= 1 - 1/8 = 7/8
or
The number of the possibilities is shown below
Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3
boys which = 3/8 + 3/8 + 1/8 = 7/8.
The probability that each child will be a girl is 1/2.
The probability of no. boys = 1/2 × 1/2 × 1/2 = 1/8
The probability of at least 1 boy = 1 - the probability of no boys.
= 1 - 1/8 = 7/8
or
The number of the possibilities is shown below
Probability of 0 boys = 1/8
Probability of 1 boy = 3 × 1/8 = 3/8
Probability of 2 boys = 3 × 1/8 = 3/8
Probability of 3 boys = 1/8
The probability of at least 1 boy is equal to the probability of 1 or 2 or 3
boys which = 3/8 + 3/8 + 1/8 = 7/8.
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