Math, asked by hateu7058, 1 year ago

Solve the problem!! ​

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Answered by Anonymous
4

 \large{ \underline{ \underline \mathfrak{answer - }}}

The present age of the man is 45 years.

 \huge \underline{ \underline \mathfrak{explanation - }}

Let the present age of the man is x years and the sum of the present ages of his two sons be y years. Then,

x=3y =>x-3y =0. .....(1)

Man's age after 5 years =(x+5) years.

Sum of the ages of his two sons after 5 years = (y+5+5)years = (y+10)years.

 \therefore(x + 5) = 2(y + 10) \implies \: x - 2y = 15...(2)

On subtracting (1)from (2),we get y=15.

Putting y=15 in (1),we get x=45

 \therefore \: x = 45 \: and \: y = 15

Hence, the present age of the man is 45 years.

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