SOLVE THE PROBLEM.
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SOLUTION:-
➠ Given :- E = { 2,4,6,8,10}
➠ (i) Let A = { x | x = n +1 , n ∈ E }
➠ thus for, 2 ∈ E, x = 3
4 ∈ E, x =5
➠ and so on , therefore A = {3,5,7,9,11}
➠ (ii) Let B ={ x | x = n², n ∈ E }
➠ so far 2 ∈ E, x =(2)²=4
4 ∈ E, x = (4)² = 16
➠ and so on, hence, B = { 4,16,36,64,100}
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➠Formulae to solve on union and intersection of two sets.
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➠Let A, B and C be any finite sets. Then
(a) n (A ∪ B) = n (A) + n (B) – n (A ∩ B)
(b) If (A ∩ B) = φ, then n (A ∪ B) = n (A) + n (B)
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