solve the problem √√2+1/√2-1
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\begin{gathered} \frac{ \sqrt{2} - 1}{ \sqrt{2} + 1} = a + b \sqrt{2} \\ \frac{ \sqrt{2} - 1 }{ \sqrt{2} + 1} \times \frac{ \sqrt{2 } - 1}{ \sqrt{2 } - 1} = a + b \sqrt{2} \\ \frac{ {( \sqrt{2} - 1) }^{2} }{2 - 1} = a + b \sqrt{2} \\ 2 + 1 - 2 \sqrt{2} = a + b \sqrt{2} \\ 3 - 2 \sqrt{2} = a + b \sqrt{2} \\ a = 3 \: and \: b = - 2\end{gathered}
2
+1
2
−1
=a+b
2
2
+1
2
−1
×
2
−1
2
−1
=a+b
2
2−1
(
2
−1)
2
=a+b
2
2+1−2
2
=a+b
2
3−2
2
=a+b
2
a=3andb=−2
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