Math, asked by gangasinghyash, 2 months ago

solve the problem √√2+1/√2-1​

Answers

Answered by dwarak87
0

Step-by-step explanation:

Hello Mate!

\begin{gathered} \frac{ \sqrt{2} - 1}{ \sqrt{2} + 1} = a + b \sqrt{2} \\ \frac{ \sqrt{2} - 1 }{ \sqrt{2} + 1} \times \frac{ \sqrt{2 } - 1}{ \sqrt{2 } - 1} = a + b \sqrt{2} \\ \frac{ {( \sqrt{2} - 1) }^{2} }{2 - 1} = a + b \sqrt{2} \\ 2 + 1 - 2 \sqrt{2} = a + b \sqrt{2} \\ 3 - 2 \sqrt{2} = a + b \sqrt{2} \\ a = 3 \: and \: b = - 2\end{gathered}

2

+1

2

−1

=a+b

2

2

+1

2

−1

×

2

−1

2

−1

=a+b

2

2−1

(

2

−1)

2

=a+b

2

2+1−2

2

=a+b

2

3−2

2

=a+b

2

a=3andb=−2

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