Question

solve the problem... ​

Answer 1

Answer:

Q 2. (d)   ( 7x - 1 ) ( 3x + 2)

Q 3. (a)   $5m^{3}a^{5}b^{3}$

Step-by-step explanation:

Q 2.

$21x^{2} +11x - 2\\21x^{2} - 3x + 14x - 2\\3x ( 7x - 1 ) + 2 ( 7x - 1 )\\( 7x - 1 ) ( 3x + 2 )$

Q 3.

L.C.M. of polynomial = $90m^{5}a^{6}b^{3}x^{2}$

H.C.F. of polynomial = $m^{3}a^{5}$

One of polynomial = $18m^{5}a^{6}x^{2}$

    a * b = { L.C.M. ( a , b ) } * { H.C.F. ( a , b ) }            

 

{ NCERT, CLASS 10, PAGE 10 and 11, CHAPTER : REAL NUMBERS }

Here, 'a' and 'b' are positive integers or polynomials

$\frac{90m^{5}a^{6}b^{3}x^{2} * m^{3}a^{5}}{18m^{5}a^{6}x^{2}}$    

$5m^{3}a^{5}b^{3}$