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1) lets consider mass of sodium sulphate required to it's 20% = n
then,
n/n+100 ×100 = 20%
100n/ n+100 = 20/100
100n = n+100 × 20/100
100n × 100/20 =n +100
100n × 5= n+ 100
500n = n+100
499n =100
n = 100/499
n= 0.20
so the amount of sodium sulphate required is 0.20g
2) percentage of solution = 110/550 × 100
= 20%
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