solve the problem..........
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tn= a+(n-1)d
80=8+(n-1)8
80=8n
Sn=n/2(a+l)
Sn=5(8+80)
Sn=440
Answered by
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Answer:
An+an=80
80-8=72, 80+8=88
8×10=80
n=10
- find S10
An=n/2
S10 =10/2×20
S10=10²-20
S10=80
- THEREFORE THE VALUE OF SUM S10 IS 40
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