Question

solve the problem............​

Answer 1

GIVEN:-

• Ratio of angles of triangle = 4:3:2

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TO FIND:-

• The angles of the triangle.

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SOLUTION:-

• $\bigstar {\sf {\blue {Let\ the\ first\ angle\ be\ 4x.}}}$
• $\bigstar {\sf {\orange {Let\ the\ second\ angle\ be\ 3x.}}}$
• $\bigstar {\sf {\green {Let\ the\ third\ angle\ be\ 2x.}}}$

Now, as we know that sum of all the angles of a triangle is 180°.

So, the equation formed is:

4x + 3x + 2x = 180°

9x = 180°

$\sf \: x = \dfrac{180}{9}$

$\boxed {\bf {\pink {x=20°}}}$

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VERIFICATION:-

On substituting the value of x as 20° in the equation,

4x + 3x + 2x = 180°

4×20° + 3×20° + 2×20° = 180°

80°+60°+40° = 180°

180° = 180°

LHS = RHS

Hence Verified!

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THE ANGLES ARE:—

The first angle = 4x

= 4×20°

=:: 80°

The second angle = 3x

= 3×20°

=:: 60°

The third angle = 2x

= 2×20°

=:: 40°

• The angles of the triangle are 40°, 60° and 80°.

Answer 2

Given :

The angles of a triangle are in ratio 4 : 3 : 2

To find :

The angles of the triangle

Solution :

Let the angles be 4x, 3x and 2x. Then,

⇒ 4x + 3x + 2x = 180° (sum of all the angles of a triangle)

⇒ 9x = 180°

⇒ x = 180/9

⇒ x = 20

Therefore,

First angle = (4 × 20)° = 80°

Second angle = (3 × 20)° = 60°

Third angle = (2 × 20)° = 40°

And hence, the angles of the triangle are 80°, 60° and 40°.