Question

solve the problem !!​

Answer 1

Given:-

• There length of a rectangular garden is 120m long.
• The width (breadth) of the rectangular garden is 80m
• Two roads having width 5m running parallel to length and breadth.

To find:-

• The cost of constructing the road at Rs. 120 per m sq.

• For this, we have to find the area of the roads.
• By naming different points.

We get two roads,

Road BCGH,

Length (l) = 80m

Breadth (b) = 5m

Area = l*b

        = 80 * 5

        = 400 m sq.

Also,

Road EFIJ,

Length (l') = 120m

Breadth (b') = 5m

Area = l*b

        = 120 * 5

        = 600 m sq.

Now,

Both the roads are intersecting so the area of PQRS is occurring two times.

Thus, we have to subtract its area once.

Each side of PQRS square is 5m,

Area of PQRS = (side)²

                       = (5)²

                       = 25 m sq.

Now,

The area of the road to be constructed is,

= (Area of BCGH + Area of EFIJ) - Area of PQRS

= 400 + 600 - 25

= 1000 - 25

= 975 m sq.

Now,

The cost of constructing the road for 1 m sq is Rs. 120

The cost for constructing the road for 975 m sq, will be

= 975 * 120

= Rs. 117000

Hence,

•The total cost will be 117000.

Answer 2

☘️ See the attachment picture for Explanation.

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