Question

solve the problem above​

Answer 1

1. area of ABC

$\frac{1}{2} \times 12 \times 16 \\ 96$

1. ACD
2. $perimeter \\ 2 + 29 + 20 \\ 70 \\ \\ semiperimeter \\ 70 \div 2 \\ 35 \\ \\ ar \: \: acd \\ \sqrt{35 \times (35 - 21)(35 - 29)(35 - 20)} \\ \sqrt{35 \times 6 \times 14 \times 15} \\ 7 \times 5 \times 3 \times 2 \\ 210$
3. ar. abcd

96 +120

=216

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