Question

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Answer 1

QUESTION



ANSWER





(1)

${x}^{2} + 3x + 2 \: \: by \: \: x + 1$




$so \: \: {x}^{2} + 3x + 2$


$= {x}^{2} + 2x + x + 2$




$= x(x + 2) + 1(x + 2)$



$(x + 1)(x + 2)$


so on dividing it by (x+1) we get



$= > \frac{(x + 1)(x + 2)}{(x + 1}$



$= (x + 2)$





Ans. 2



${x}^{2} - 7x - 18 \: \: by \: x - 9$




${x}^{2} - 7x - 18$

on FACTORIES



${x}^{2} - 9x + 2x - 18$




$x(x - 9) + 2(x - 9)$



$(x - 9)(x + 2)$


on dividing it by (x-9). we get


$\frac{(x - 9 )\: (x + 2)}{(x - 9)}$


$= (x + 2)$




Ans 3


${p}^{2} + 6p + 8 \: \: by \: p + 2$




${p}^{2} + 6p + 8$


$= {p}^{2} + 4p + 2p + 8$



$p(p + 4) + 2(p + 4)$




$(p + 2)(p + 4)$






on dividing it by. (p+2) we get


$\frac{(p + 2)(p + 4)}{(p + 2)}$


$= \: (p + 4)$


Ans 4


${p}^{2} - p - 42 \: by \: \: p + 6$




$= \frac{ {p}^{2} -p - 42}{(p + 6)}$



$= \frac{ {p}^{2} - 7p + 6p - 42 }{p + 6}$


$\frac{p(p - 7) + 6(p - 7)}{p + 6}$






$= (p + 7)$



5Ans

$\frac{ {y}^{2} + 12y + 35 }{y + 7}$



$\frac{ {y}^{2} + 7y + 5y + 35 }{y + 7}$



$\frac{y(y + 7) + 5(y + 7)}{y + 7}$



$= y + 5$






Ans 6

$\frac{ {z}^{2} - 10z + 16}{z - 2}$




$\frac{ {z}^{2} -8 z - 2z + 16 }{z - 2}$




$\frac{z(z - 8) - 2(z - 8)}{z - 2}$



$\frac{(z - 2)(z - 8)}{z - 2}$


$= z - 8$




And 7

${x}^{4} - 3 {x}^{2} - 10x \: by \: \: {x}^{2} + 5$

put
${x}^{2} = y$


$\frac{ {y}^{2} - 3y - 10 }{y + 5}$


$\frac{ {y}^{2} - 5y + 2y - 10 }{y + 5}$



$\frac{y(y - 5) + 2(y - 5)}{y + 5}$




$= y + 2$



now replace value of y


${x}^{2} + 2$
is the ans




Ans 8.

$\frac{ {x}^{2} - 7x + 12}{x - 4}$




$\frac{ {x - 4x - 3x + 12} }{x - 4}$



$\frac{x(x - 4) - 3(x - 4)}{x - 4}$




$\frac{(x - 4)( x - 3)}{x - 4}$



$= (x - 3)$

Answer 2

Answer:

easyyyyy

Step-by-step explanation: