Question

Solve the problem by Elimination by equating Coefficients method.
No one can solve this problem

Answer 1

Hey
First you can find the value of 2/y-1 then put the value of 2/y-1 in equation 2 then you get the value of second equation then put in 1 equation
Hope you solve it

Answer 2

Hiii friend,

5/X+1 + 2/Y-1 = 1/2........(1)

2/Y-1 + 10/X+1 = 5/2......(2)

Let , 1/X+1 = U and 1/Y-1 = V and put the values in equation (1) and (2) .

Then equation (1) and equation (2) becomes,

5U + 2V = 1/2

2(5U +2V) = 1

10U + 4V = 1.....(3)

And,

2V + 10U = 5/2

2(2V +10U) = 5

4V + 20U = 5......(4)

From equation (3) we get,

10U + 4V = 1

10U = 1-4V

U = 1-4V/10......(5)

Putting the value of U in equation (4)

4V + 20U = 5

4V + 20 × (1-4V/10) = 5

4V + 2(1-4V) = 5

4V + 2 - 8V = 5

-4V = 5-2

-4V = 3

V = -3/4

Putting the value of V in equation (5)

U = 1-4V/10 => 1 - 4 × -3/4/10 => 1+3/10 = 4/10 = 2/5.

PUTTING THE VALUE OF V IN,

1/Y-1 = V

1/Y-1 = -3/4

4 = -3(Y-1)

-3Y +3 = 4

-3Y = 4-3

Y = -1/3.

PUTTING THE VALUE OF U IN,



1/X+1 = U

1/X+1 = 2/5

5 = 2(X+1)

5 = 2X+2

2X = 5-2

2X = 3

X = 3/2.

Hence,

X = 3/2 and Y = -1/3.

HOPE IT WILL HELP YOU...... :-)