solve the problem by seeing the picture
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Initial velocity,u=0 Time taken,t =10s Distance travelled,s=100m We know that, S=ut +1/2at^2 Therefore 100=(0×10)+[1/2a(10)^2] 100=50a A=100/50=2m/s^2 We know that, F=ma 1 metric tonne= 1000kg 5 metric tonnes =1000×5= 5000kg F=5000kg×2m/s^2 F=10000kgm/s^2or N Therefore option c is correct
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As the initial velocity is 0 so s= 1/2*a*(t^2). Now put the values to get acceleration and then find force.
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