Solve the problem for x
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Friend here is your answer please mark braineliest for my effort
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if you see the values being reciprocals of each other, then we should substitute the values as y or any other alphabets and its reciprocals.
here, it goes: 2y - 3/y = 5
therefore, 2y^2 - 3 =5y
so, we get the proper equation as: 2y^2 - 5y -3=0
now, we factorise it, 2y^2 - 6y +y -3 = 0 [since the sum= -5 and product=6]
2y(y-3) -1(y-3) = 0
(2y-1) (y-3)=0
the values of y are: 1/2 and 3
putting y = 3, we get:
2x-1/x+3 = 3
2x-1 = 3x + 9
3x-2x= -9-1
x = 10
now by putting 1/2, we get:
2x-1/x+3 = 1/2
4x-2 = x+3
3x = 5, x=5/3
therefore the values of x are : 5/3 and 10
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