Question

solve the problem given ​

Answer 1

ola!!

⤵⤵Answer⤵⤵

Lcm(12,42)=10m+4...................................(1)

also by solving, we get

lcm(12,42)=84.................................(2)

by Comparing 1 and 2

10m+4=84

10m=80

m=8

tysm❤

Answer 2

Question 1.

LCM of 12 and 42 is 10m +4 then find the value of m.

Solution:

LCM of 12 = 2 × 2 × 3

LCM of 42 = 2 × 3 × 7

› LCM of both 12 and 42 = 2 × 2 × 3 × 7

= 84

Now ..

→ 10m + 4 = 84

→ 10m = 80

→ m = 8

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$\huge{\bold{m\:=\:8}}$

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Question2.

What type of decimal expansion of a number 441/2²×5³×7 has?

Solution:

Fraction = $\dfrac{Numerator}{Denominator}$

→ $\dfrac{441}{ {2}^{2} {5}^{3}7 }$

→ $\dfrac{ {3}^{2} {7}^{2} }{ {2}^{2} {5}^{3}7 }$

→ $\dfrac{ {3}^{2} 7 }{ {2}^{2} {5}^{3}}$

→ $\dfrac{ 9(7) }{ {2}^{2} {5}^{3}}$

→ $\dfrac{ 63 }{ {2}^{2} {5}^{3}}$

Above denomination is in the form ${2}^{m}{2}^{n}$

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$\textbf{So, the decimal expansion of the number}$

$\textbf{is Terminal decimal expansion.}$

_________ [ANSWER ]

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