Question

solve the problem given!!​

Answer 1

GIVEN :–

• Half life $\bf \:( t_{ \frac{1}{2} })$ of $\bf C^{19}$ is 5700 years.

TO FIND :–

• Decay constant $(\lambda)$= ?

SOLUTION :–

• We know that –

$\\ \large \implies { \boxed{ \bf \: t_{ \frac{1}{2} } = \dfrac{0.693}{ \lambda}}}$

• Now put the values –

$\\ \large \implies \bf \: 5700= \dfrac{0.693}{ \lambda}$

$\\ \large \implies \bf \: \lambda= \dfrac{0.693}{5700}$

• We should write this as –

$\\ \large \implies \bf \: \lambda= \dfrac{693}{5700000}$

$\\ \large \implies \bf \: \lambda= \dfrac{693}{57 \times {10}^{5} }$

$\\ \large \implies \bf \: \lambda= \dfrac{693}{57} \times {10}^{ - 5}$

$\\ \large \implies \large{ \boxed{ \bf \lambda=12.26\times {10}^{ - 5} \: year ^{ - 1} }}$

• Hence , Option (1) is correct.

Answer 2

☘️ See the attachment picture for Explanation.

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