Question

solve the problem given below

Answer 1

Answer:

let zeroes of quadratic polynomial ax²+bx+c be p, pn

(x-p) (x-np) =x²-x(p+np) +np²=ax²+bx+c

comparing on both sides we get

a=1

c=np²

b=-p(n+1) →b²=p²(n+1) ²→nb²=np²(n+1) ²

ac=1(np²) →ac=np²

so, bn²=ac(n+1) ²