CBSE BOARD X, asked by BRAINLYDLT, 11 months ago

solve the problem given in the attachment ​

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Answers

Answered by DeviIQueen
4

OLA ✌ ❤

Given :

1. H.C.F and L.C.M of two

number are 25 and 5525.

2. One of the given number

is = 325

==================

To find :

We have to find other

number.

==================

As we know that

H.C.F × L.C.M =

Product of the two

number.

==================

Let us take the other

number as 'x'.

==================

So we have to solve this

equation

⇒ 25 × 5525 = x × 325

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Let us solve ,

⇒ 25 × 5525 = x × 325

⇒ 138125 = x × 325

⇒ x = \dfrac{123125}{325}

325

123125

⇒ x = 425

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\Huge{\boxed{x=425}}

x=425

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Therefore the other number

be 425

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Answered by daksh9934
1

Explanation:

Hi

HCF = 131

HCF = 131LCM = 8253

HCF = 131LCM = 8253One of the number = 917

HCF = 131LCM = 8253One of the number = 917We know that

HCF = 131LCM = 8253One of the number = 917We know thatLCM × HCF = Product of two numbers

HCF = 131LCM = 8253One of the number = 917We know thatLCM × HCF = Product of two numbers Other number =

HCF = 131LCM = 8253One of the number = 917We know thatLCM × HCF = Product of two numbers Other number = ∴ The other number is 1179

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