Question

solve the problem in attachment . NO UNWANTED AND UNLOVED UNUSEFUL ANSWERS.​

Answer 1

Given question:-

If x=4-√15, then find the value of

$(x + \frac{1}{x} ) {}^{2}$

Answer:

Putting the given value of x, in the relation

$\tt{(4 - \sqrt{15} + \frac{1}{4 - \sqrt{15} } )} \\ \tt{ \frac{(4 - \sqrt{15} ){}^{2} + 1 }{4 - \sqrt{15} } } \\ \tt{ \frac{16 + 15 - 8 \sqrt{15} + 1}{4 - \sqrt{15} } } \\ \tt{ \frac{32 - 8 \sqrt{15} }{4 - \sqrt{15} }} \\ \tt{ \frac{8(4 - \sqrt{15} )}{4 - \sqrt{15} } } \\ \tt \blue{ \boxed{</strong><strong>6</strong><strong>4</strong><strong>}}$

Hope my answer will help you.

Sorry I have missed squaring..