Question

Solve the problem no 14

If you don't know so plz don't answer anything. ​

Answer 1

Answer:

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Answer 2

GIVEN : $\angle{ABC}$ = 88°. AB is produced to point D. Ray BM bisects $\angle{CBD}$.

FIND : $\angle{ABM}$ and reflex $\angle{MBC}$.

Solution :

*Refer the attachment for figure.

Now.. ABC is a line

So,

→ $\angle{ABC}\:+\:\angle{CBD}$ = 180°

→ 88° + $\angle{CBD}$ = 180°

→ $\angle{CBD}$ = 180° - 88°

→ $\angle{CBD}$ = 92°

Now..

BM bisects $\angle{CBD}$ =

So,

→ 2$\angle{MBC}$ = $\angle{CBD}$

→ $\angle{MBC}$ = $\dfrac{\angle{CBD}}{2}$

→ $\angle{MBC}$ = $\dfrac{92}{2}$

→ $\angle{MBC}$ = 46°

What is $\angle{ABM}$ ?

=> $\angle{ABM}$ = $\angle{ABC}$ + $\angle{CBM}$

→ 88° + 46°

→ 134°

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