Question

Solve the Problem
No Spam.
NO.2 only​

Answer 1

Answer:

(i) volume of lead piece = V=v_2-v_1V=v2−v1

v_{1\ }=\ 20\ ml\ ,\ v_2\ =\ 30\ mlv1 = 20 ml , v2 = 30 ml

= 30 - 20 ml = 10 ml

(ii) density of lead piece = d=\frac{M}{V}d=VM

= \frac{115}{10}10115

= 11.5\ kg\ cm^{-3}11.5 kg cm−3

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