Question

Solve the problem please ​

Answer 1

Answer:

in triangle ∆DGB and ∆EFC

use similarity

after this

we get,

∆ DGB is similar to ∆ CFE

from this we get the ratios of sides

DG/CF = BG/FE = BD/CE

from this

we get

DG/CF = BG/FE

DG.FE = BG x FC ....(1)

as DG = FE = FGsides of square

from ...(1) we get

FG.FG = BG x FC

FG ² = BG x FC

hope you understand