Question

Solve the problem please​

Answer 1

Answer:

Step-by-step explanation:

5^x-1 * 5^[2[x-4]] =1

= 5^[x-1[2x-8]]=1

= 5^[2x^2-8x-2x+8]=1                    [5^0=1] this is the only possible case.

2x^2-8x-2x+8=0

2x[x-4]-2[x-4]=0

[2x-2] [x-4]=0

2x-2=0 or x-4=0

x=1 or 4