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given
s ( distance ) = 500 m = 0. 5 km
u ( initial velocity ) = 0
t ( time ) = 30 sec = 3 / 360 hr
v (final velocity ) = ?
by formula
s = ut + 1/2 at^2
0.5 = 0 + 1/2 a ( 3/ 360 ) ^2
0.5 = 1/2 (a) 9 / 129600
0.5 = 9 / 259200 (a)
a = 0.5 . 259200 / 9
a = 5 . 259200 / 9 . 10
a = 129600/9
a = 14400 km / h ^2
v = u + at
v = 0 + 14400 ( 3 / 360) hr
v = 120 km / hr
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