Question

solve the problem plz ​

Answer 1

Answer:

$\large\boxed{\sf{\dfrac{19}{2}}}$

Step-by-step explanation:

Given that,

• x = 5
• y = 3

To find the value of,

• $\dfrac{ {x}^{3} + {y}^{3} }{ {x}^{2} - {y}^{2} }$

We can therefore write,

$= \dfrac{(x + y)( {x}^{2} - xy + {y}^{2}) }{ {x}^{2} - {y}^{2} } \\ \\ = \dfrac{(x + y)( {x}^{2} -xy + {y}^{2}) }{(x + y)(x - y)} \\ \\ = \frac{( {x}^{2} - xy + {y}^{2}) }{(x - y)}$

Now, substitute the values of x and y, we get,

$= \dfrac{ {5}^{2} -( 5 \times 3 )+ {3}^{2} }{5 - 3} \\ \\ = \dfrac{25 - 15 + 9}{2} \\ \\ = \dfrac{10 + 9}{2} \\ \\ = \frac{19}{2}$

Hence, the required value is 19/2.

Answer 2

Answer:

5^3+3^3/5^2-3^2=125+27/25-9=162/16=10.12