solve the problem plz
Attachments:
Answers
Answered by
0
Answer- The above question is from the chapter 'Real Numbers'.
The question is an applicative one.
A merchant has 3 kinds of oil i.e. 120 litres, 180 litres and 240 litres. He wants to put them in a container which can hold the greatest capacity of oil.
Clearly, the tin should hold even the least kind of oil available.
HCF(120, 180, 240) = Greatest capacity of tin to hold 3 kinds of oil.
← H.C.F. 120, 180, 240
Thus, we will find the HCF of 120, 180 and 240 by prime factorisation method.
120 = 2 × 2 × 2 × 2 × 3 × 5 = 2⁴ × 3 × 5
180 = 2 × 2 × 3 × 3 × 5 = 2² × 3² × 5
240 = 2 × 2 × 2 × 2 × 2 × 3 × 5 = 2⁵ × 3 × 5
HCF(120, 180, 240) = 2² × 3 × 5 = 60 litres
∴ Greatest capacity of tin = 60 litres.
Similar questions