Solve the problem plz......
Answers
Answer:
Solution :-
Let the actual price of the TV be Rs. 'x' and of the fridge be Rs. 'y'.
Situation -1
By selling the TV at 5 % gain and fridge at 10 % gain, the shopkeeper gains Rs. 2000.
⇒ 5x/100 + 10y/100 = 2000
⇒ x/20 + y/10 = 2000/1
Taking the L.C.M. of the denominator and then solving it, we get.
⇒ (x + 2y)/20 = 2000
⇒ x + 2y = 40000 ...........................(1)
Situation - 2
By selling the TV at 10 % gain and fridge at 5 % loss, the shopkeeper gains Rs. 1500. The loss is indicated with the negative sign.
⇒ 10x/100 - 5y/100 = 1500
⇒ x/10 - y/20 = 1500/1
Taking the L.C.M. of the denominator and then solving it, we get.
⇒ (2x - y)/20 = 1500
⇒ 2x - y = 30000 ........................(2)
Now, multiplying the (1) by 2, and then subtracting 2 from it, we get.
First Multiplying (1) by 2 = 2*[(x + 2y) = 40000]
⇒ 2x + 4y = 80000
Now, subtracting (2) from the above.
2x + 4y = 80000
2x - y = 30000
- + -
________________
5y = 50000
__________________
⇒ 5y = 50000
⇒ y = 50000/5
⇒ y = 10000
The actual price of fridge is Rs. 10000.
Now putting the value of y = 10000 in (1), we get.
⇒ x + 2y = 40000
⇒ x + (2*10000) = 40000
⇒ x = 40000 - 20000
⇒ x = 20000
Hence, the actual price of TV is Rs. 20000 and actual price of fridge is Rs. 10000
Answer:
Actual price of T.V. is Rs. 20,000 and fridge is Rs. 10,000
Step-by-step explanation:
Let the price of the T.V. be Rs. x and the price of the fridge be Rs. y. Then, we have:
5x/100 + 10y/100 = 2000
⇒5x + 10y = 200000
⇒5(x + 2y) = 200000
⇒x + 2y = 40000 ...(i)
And, 10x/100 - 5y/100 = 1500
⇒10x - 5y = 150000
⇒5(2x - y) = 150000
⇒2x - y = 30000 ...(ii)
Now, multiplying (ii) by 2, we get:
4x - 2y = 6000 ...(iii)
Adding (i) and (iii),
x + 4x = 40000 + 60000
⇒5x = 100000
⇒x = 20000
Putting x = 20000 in (i), we get:
20000 + 2y = 40000
⇒2y = 20000
⇒y = 10000
Therefore, cost of T.V. is Rs. 20000 and cost of fridge is Rs.10000
HOPE IT HELPS !!!