Question

solve the problem :
$ax {}^{2} = 0$
where 'a' not equal to 0​

Answer 1

Answer:

ax²=0

x²= 0/a

x²=0 { a ≠0, so 0/a will be zero}

x=√0

x= +0 or -0

We know that 0 is neither +ve nor -ve,

Do, x= 0

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