Question

solve the problem
$y = \frac{1}{ \sqrt{x { }^{2} + x + 1} }$
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Answer 1

Answer:

$y = \frac{ \sqrt{ {x}^{2 } + x + 1} }{ {x}^{2} + x + 1 }$

$x = - \frac{y - \sqrt{ { - 3y}^{2} + 4} }{2y}$

OR

$x = - \frac{y + \sqrt{ { - 3y}^{2} + 4 } }{2y}$

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Answer 2

Answer:

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