Math, asked by radhasharma4ever09, 23 hours ago

solve the problem this ​

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Answered by dibyansuptnk
2

Answer:

Let the digit at tens place be x then digit at ones place will be (9-x).

Original two digit number = 10x + (9-x)

After interchanging the digits, the new number = 10(9-x) + x

According to the question,

10x + (9-x) + 27 = 10(9-x) + x

⇒ 10x + 9 - x + 27 = 90 - 10x + x

⇒ 9x

+36 = 90 - 9x

⇒ 9x + 9x = 90 - 36

⇒ 18x = 54

⇒ x = 3

Original number = 10x + (9-x) = (10×3) + (9-3) = 30 + 6 = 36

Thus, the number is 36

Answered by himanibhagat182
1

Step-by-step explanation:

the answer is 2

i hope it help you

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