Question

Solve the problem using quadratic functions.

A rectangle has a perimeter of 100 cm. Find the greatest possible area for the rectangle.​

Answer 1

Answer:

perimeter100 મુજે

perimeter of rectangle =2(l+b)

====100=2(l+b)

====lb= 2/100

===== lb === 50

Answer 2

Answer:

We know the perimeter of rectangle = 2*(length + width) unit.

Here 2*(length + width) = 100 cm

So, length + width = 100/2 = 50 cm

In rectangle length is always bigger than width.

By assuming, If length & width equals, it becomes square and area is the biggest i.e. 25 * 25 = 625 sq cm.

But, length will be bigger. Hence greatest possible area of this rectangle will be if length is 26 cm and width is 24 cm. So area will be 26*24 = 624 sq cm.

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