Question

Solve the problem which is mentioned in the attachment !
❗ No irrelevant stuff ❗
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Answer 1

★Given:-

• Manjit requires 16% to pàss.
• Marks she got = 308
• Falls short by 92

★To find:-

• The maximum number she could have got.

★Solution:-

As she got 308 marks and falls short by 92 to pàss. Therefore,the pàssing marks will be the sum of the marks she obtained & the no.of.marks she falls's short by.That is,

Pàssing marks = 308 + 92

                         = 400

Let the maximum number of marks is 'x'.

Given that Manjit requires 16% to pàss.

Therefore,

➺400 is the 16% of x

➺x(16/100) = 400

➺16x = 400(100)

➺16x = 40000

➺x = 40000/16

➺x = 2500

Hence,the maximum no of marks she could have got is 2500.

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Answer 2

➪Hey Mate, Due to problems, technical issues faced by Brainly, I had written the answer and attached an attachment for you! Please do go through it.