Math, asked by Anonymous, 2 months ago

Solve the problem which is mentioned in the attachment !
❗ No irrelevant stuff ❗

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Answers

Answered by EnchantedGirl
41

Given:-

  • Manjit requires 16% to pàss.
  • Marks she got = 308
  • Falls short by 92

To find:-

  • The maximum number she could have got.

Solution:-

As she got 308 marks and falls short by 92 to pàss. Therefore,the pàssing marks will be the sum of the marks she obtained & the no.of.marks she falls's short by.That is,

Pàssing marks = 308 + 92

                         = 400

Let the maximum number of marks is 'x'.

Given that Manjit requires 16% to pàss.

Therefore,

➺400 is the 16% of x

➺x(16/100) = 400

➺16x = 400(100)

➺16x = 40000

➺x = 40000/16

x = 2500

Hence,the maximum no of marks she could have got is 2500.

__________

Answered by CopyThat
21

Hey Mate, Due to problems, technical issues faced by Brainly, I had written the answer and attached an attachment for you! Please do go through it.

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