Question

solve the problem : (x-3)whole square

Answer 1

The question given is in the form ( a - b )².

( a - b )² = a² + b² - 2ab

=> ( x - 3 )² = ( x )² + ( 3 )² - 2 ( x) ( 3 )

=> ( x - 3 )² = x² + 9 - 6x

=> ( x - 3 )² = x² - 6x + 9

Answer 2

Answer:

The required answer is $(x-3)^{2} =x^{2} -6x+9$

Step-by-step explanation:

Concept:

The square of a binomial can be calculated using the$(a-b)^{2}$ formula. One of the often used algebraic identities is a minus b whole square formula. The formula for the square of a term difference is another name for this one.

In this formula, we first determine the square of the difference between the two terms and then use algebraic identity to solve it.

Given:

The expression is $(x-3)^{2}$

To find:

The objective is to solve the given expression.

Solution:

The given expression is $(x-3)^{2}$

We know, $(a-b)^{2} =a^{2} -2ab+b^{2}$

$(x-3)^{2} =x^{2} -2$ × $x$ × $3$ $+(3)^{2}$

⇒$(x-3)^{2} =x^{2} -6x+9$

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