Math, asked by sheethu69, 1 year ago

solve the problem
y+1/y-1=2y+3/2y+5

Answers

Answered by srishti785325
3
y+1. 2y+3

____=_____
y-1. 2y+5
2y+5(y+1)=y-1(2y+3)
2y^2+5=2y^2-3
2y^2-2y^2=-3-5
0=-8
y=-8
hope it helps you
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sheethu69: i cant understand
Answered by rathipriya226
9
y+1/y-1=2y+3/2y+5
2y+5(y+1)=2y-3(y-1)
2y(y+1)+5(2y+1)=2y(y-1)-3(y-1)
2y square+2y+10y+5=2ysquare-2-3y+3
2y square-2ysquare=-3y-2y+10y+3-5
0=-5y+10y-2
0=5y-2
5y-2=0
5y=0+2
5y=2
y=2/5

have a great day
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