Question

Solve the problems:
(1st problem) In an animal park, there were total 300 animals.
2/5 of the animals were zebras,
1/3 were monkeys and the rest were tigers.
Find the percentage of the tigers.
(2nd Problem) Ali scores 55 out of 70 marks in his Maths class assessments in January,
75 out of 90 in February and 83 out of 120 in March.
In which month did he perform the best?
Show your working clearly

Answer 1

Question:1

Given:

The total number of animals=300

The number of zebra=2/5

The number of monkeys=1/3

The number of tigers =X

A.T.Q

==>Number of zebra=2/5×300=120

==>Number of monkeys=1/3×300=100

==>Number of tigers=Total animal-(N of Z+N of M)

==>Number of tigers=300-(120+100)

==>Number of tigers=300-220

==>Number of tigers=80

Hence,

The percentage of tigers=80/300×100=26.66%

Question:2

Given:

Ali in math

The score in January=55/70

The score in February=75/90

The score in March=83/120

To Find

• Best performance in which month

Here we have to arrange the score in ascending order

Step:Lcm of 70 90 120=2520

step: compare the fraction

step:make all denominator same

Now,

55/70=55×36/70×36=1980/2520

75/90=75×28/90×28=2100/2520

83/120=83×21/120×21=1743/2520

It's clearly mentioned above

in the month of February he performed best

because he secured good marks

Answer 2

1)

Given:

• Total animals in animal park= 300
• No. of Zebras= 2/5 of total
• No. of Monkeys= 1/3 of total
• Rest are Tigers

To Find:

• Percentage of Tigers in animal park

Solution:

$\longrightarrow\sf{Number\:of\:Zebras=\dfrac{2}{5}\:of\:300}$

$\longrightarrow\sf{Number\:of\:Zebras=\dfrac{2}{5}\times300}$

$\longrightarrow\sf{Number\:of\:Zebras=2\times60}$

$\longrightarrow\sf{Number\:of\:Zebras=120}$

Also,

$\longrightarrow\sf{Number\:of\:Monkeys=\dfrac{1}{3}\:of\:300}$

$\longrightarrow\sf{Number\:of\:Monkeys=\dfrac{1}{3}\times300}$

$\longrightarrow\sf{Number\:of\:Monkeys=100}$

So,

$\sf{Number\:of\:Tigers=Total\:Animals-(Number\:of\:Zebras+Number\:of\:Monkeys)}$

$\sf{Number\:of\:Tigers=300-(120+100)}$

$\sf{Number\:of\:Tigers=300-220}$

$\sf{Number\:of\:Tigers=80}$

$\sf{Percentage\:of\:Tigers=\dfrac{Total\:no.\:of\:Tigers}{Total\:no.\:of\:Animals}\times100}$

$\sf{Percentage\:of\:Tigers=\dfrac{80}{300}\times100}$

$\sf{Percentage\:of\:Tigers=\dfrac{80}{3}\%}$

$\sf{Percentage\:of\:Tigers=26.67\%}$

2)

Given:

Scores of Ali in:

• January- 55 out of 70

• February- 75 out of 90

• March- 83 out of 120

To Find:

In which month did Ali perform the best

Solution:

To find the best performance, we have to find percentage of Ali in each month and the best percentage will give the best performance

In January

$\sf{Percentage\:of\:Ali=\dfrac{Marks\:Obtained}{Total\:Marks}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{55}{70}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{550}{7}\%}$

$\sf{Percentage\:of\:Ali=78.57\%}$

In February

$\sf{Percentage\:of\:Ali=\dfrac{Marks\:Obtained}{Total\:Marks}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{75}{90}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{750}{9}\%}$

$\sf{Percentage\:of\:Ali=83.34\%}$

In March

$\sf{Percentage\:of\:Ali=\dfrac{Marks\:Obtained}{Total\:Marks}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{83}{120}\times100}$

$\sf{Percentage\:of\:Ali=\dfrac{830}{12}\%}$

$\sf{Percentage\:of\:Ali=69.16\%}$

So, in February Ali got highest percentage

Therefore, in February Ali did the best performance