Question

solve the problems????​

Answer 1

Explanation:

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH

2

Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C

2

H

4

Cl

2

Answer 2

Answer:

Answer:

Calculate moles of each element - divide

% by atomic mass

C=19.998/12.011 = 1.665

H= 3.331/ 1.008 = 3.305

N= 23.320 / 14.007 = 1.665

O= 53.302 / 15.999 = 3.332

Divide through by smallest

C=1

H=2

N=1

O = 2 ( small rounding is accepted)

Empirical formula = CH2NO2

Formula mass = 12.011 +1.008'2 + 14.007 + 15.999:2 = 60.03 g/formula unit

Formula units in 1 molecule = 120.07 /

60.03 = 2

Molecular formula = ( CH2NO2)2 = C2H4N204 (1,2-dinitroethane.)