Question

Solve the problems.
Find the median of first 10 even numbers?​

Answer 1

Answer:

10/2th +(10/2+1)th . Then, 5th + 6th/2 = 10+12/2= 11. It is the median.

Answer 2

$\underbrace{\large{\underline{\sf Understanding \: the \: concept : }}}$

To find median firstly we should arrange all the observation in ascending order then we should check the sequence and find middle term in that sequence of ascending order & If there are even number of observations there is no middle time right? So, We should check and find out the two middle observations and then divide it by 2.

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As we know that,

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$\sf {First \: 10 \: Even \: numbers} \begin{cases} \sf{2,4,6,8,10,12,14,16,18,20 } \end {cases}$

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$\underline{\textbf{ \textsf{Finding \: median :}}} \\ \\ \\ \sf : \implies 2,4,6,8,10,12,14,16,18,20 \\ \\ \\ \sf : \implies \cfrac{1}{2} \times (10 + 12) \\ \\ \\ \sf : \implies \cfrac{(10 + 12)}{2} \\ \\ \\ \sf : \implies \cfrac{22}{2} \\ \\ \\ \boxed{\bf : \implies 11}$

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Hence, The median of 1st ten even numbers is 11.

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$\boxed {\begin{array}{cc}\\  \dag \: \underline{\Large\bf Formulas\:of\:Statistics} \\ \\ \bigstar \: \underline{\rm Mean:} \\ \\ \bullet\sf M=\dfrac {\Sigma x}{n} \\ \\ \bullet\sf M=a+\dfrac {\Sigma fy}{\Sigma f} \\ \\ \bullet\sf M=A +\dfrac {\Sigma fy^i}{\Sigma f}\times c \\ \\ \bigstar \: \underline{\rm Median :} \\ \\ \bullet\sf M_d=\dfrac {n+1}{2} \:\left[\because n\:is\:odd\:number\right] \\ \\ \bullet\sf M_d=\dfrac {1}{2}\left (\dfrac {n}{2}+\dfrac {n}{2}+1\right)\:\left[\because n\:is\:even\:number\right] \\ \\ \bullet\sf M_d=l+\dfrac {m-c}{f}\times i \\ \\ \bigstar \: {\boxed{\sf M_0=3M_d-2M}}\end {array}}$