Solve the problems
Q1. Find the area of a square whose side is 6cm.
Q2. Find the area of a rectangular shape whose length is 55 cm and breadth is 40 cm.
Q3. Find the area of a triangle whose base is 15cm and height is 30cm.
Q4. Find the area of a circle whose radius is 25cm.
Answers
Answer :-
1. A = 36cm²
2.
Question 9
Q6) A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also, find which shape encloses more area?
Solution
Transcript
Solution:
Length= 40cm
Breadth= 22cm
Perimeter of the rectangle= Length of the wire
=2(l+b)= 2(40cm + 22cm)
=2\times622×62cm = 124cm
Now, the wire is rebent into a square.
Perimeter= 124cm
4\times side=1244×side=124
Therefore side= \frac{124}{4}
4
124
cm= 31cm
So, the measure of each side= 31cm
Area of rectangular shape= l\times bl×b
=40cm\times22cm40cm×22cm
=880cm^2880cm
2
Area of a square shape= \left(Side\right)^2(Side)
2
=\left(31\right)^2=961cm^2(31)
2
=961cm
2
Since 961cm^2\ >\ 880cm^2961cm
2
> 880cm
2
Hence, the square encloses more area.
3.
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1)area=(side)²
= 6×6
= 36 cm².
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2) let the rectangle length =l =40cm
breadth =b =22 cm
let the side of a square = a cm
if the same wire is rebent in the shape of a square then
perimeter of a square=perimeter of rectangle
4a=2(l+b)
4a =2(40+22)
4a =2*62
a =2*62/4
a=31 cm
therefore side of a square = a =31cm
area of the rectangle =l*b= 40*22=880 cm^2
area of the square=a^2 = (31)^2 =961 cm^2.
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3)Answer: 225cm2
Step-by-step explanation:
1/2×b×h
1/2×30×15
15×15=225cm2
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4)
Area of circle =πr²
Given,r =25cm